You are climbing a staircase. It takes n
steps to reach the top.
Each time you can either climb 1
or 2
steps. In how many distinct ways can you climb to the top?
Example 1:
Input: n = 2 Output: 2 Explanation: There are two ways to climb to the top. 1. 1 step + 1 step 2. 2 steps
Example 2:
Input: n = 3 Output: 3 Explanation: There are three ways to climb to the top. 1. 1 step + 1 step + 1 step 2. 1 step + 2 steps 3. 2 steps + 1 step
Constraints:
1 <= n <= 45
solution:
class Solution {
public:
vector<int>memo{vector<int>(46, -1)};
int climbStairs(int n) {
if( n == 0)
return 1;
else
if(n < 0)
return 0;
if(memo[n] != -1)
return memo[n];
int n1 = climbStairs(n-1);
int n2 = climbStairs(n-2);
int cp = n1+n2;
return memo[n] = cp;
}
};
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