334. Increasing Triplet Subsequence
Given an integer array nums
, return true
if there exists a triple of indices (i, j, k)
such that i < j < k
and nums[i] < nums[j] < nums[k]
. If no such indices exists, return false
.
Example 1:
Input: nums = [1,2,3,4,5] Output: true Explanation: Any triplet where i < j < k is valid.
Example 2:
Input: nums = [5,4,3,2,1] Output: false Explanation: No triplet exists.
Example 3:
Input: nums = [2,1,5,0,4,6] Output: true Explanation: The triplet (3, 4, 5) is valid because nums[3] == 0 < nums[4] == 4 < nums[5] == 6.
Constraints:
1 <= nums.length <= 5 * 105
-231 <= nums[i] <= 231 - 1
solution:
class Solution {
public:
bool increasingTriplet(vector<int>& nums) {
int left = INT_MAX;
int mid = INT_MAX;
for(int i =0 ; i < nums.size() ; i++)
{
if(nums[i] > mid)
return true;
else
if(nums[i] < left)
left = nums[i];
else
if( nums[i] > left && nums[i] < mid)
mid = nums[i];
}
return false;
}
};
Comments
Post a Comment