7. Reverse Integer| Leetcode solution

 7. Reverse Integer

Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.

Assume the environment does not allow you to store 64-bit integers (signed or unsigned).

 

Example 1:

Input: x = 123
Output: 321

Example 2:

Input: x = -123
Output: -321

Example 3:

Input: x = 120
Output: 21

 

Constraints:

• -231 <= x <= 231 - 1

solution :

class Solution {

public:

    int reverse(int x) {

        long long  result = 0;

        if(x == INT_MIN)

            return 0;

         int temp = x;

           if(x < 0)

            temp = -x;

        while(temp!= 0)

        {

            int once = temp %10 ;

            if(x < 0)

            {

                if(-(result*10+once) < INT_MIN )

                    return 0;

            }

            else

            {

               if(result*10+once > INT_MAX )

                    return 0;

            }

            result = result*10 + once;

            temp = temp/10;

            

        }

        if(x < 0)

            return -result;

        return result;

    }

};